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Jun 25, 2020 · What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) + 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline y Superscript 5 Baseline) 4 x (RootIndex 3 StartRoot 2 y EndRoot) + 12 x squared y (RootIndex 3 StartRoot 2 y squared EndRoot) 8 x (RootIndex 3 StartRoot x y EndRoot) + 12 x cubed y squared (RootIndex 3 StartRoot 6 y EndRoot) 16 x cubed y (RootIndex 3 StartRoot 2 y ... Answer:Which expression is equivalent to RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Baseline EndRoot? ... 8 a cubed b cubed c Superscript 4 Baseline (RootIndex 3 StartRoot b c EndRoot) 8 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot) Send. mel-nik [20] 3 years ago. 5 0.simplify StartRoot 16 r Superscript 6 Baseline EndRoot. simplify StartRoot 16 r Superscript 6 Baseline EndRoot ...How are the graphs of the functions f(x) = StartRoot 16 EndRoot Superscript x and g(x) = RootIndex 3 StartRoot 64 EndRoot Superscript xrelated? The functions f(x) and g(x) are equivalent. The function g(x) increases at a faster rate. The function g(x) has a greater initial value. The function g(x) decreases at a faster rate.

Solution: Step 1: Again, we need to find the largest perfect square that divides into 108. Such number is 36. Step 2: Write 108 as the product of 36 and 3. ( 108 = 36 * 3 ) Step 3: Use the product rule:Algebra. Simplify square root of 64x^8. √64x8 64 x 8. Rewrite 64x8 64 x 8 as (8x4)2 ( 8 x 4) 2. √(8x4)2 ( 8 x 4) 2. Pull terms out from under the radical, assuming positive real numbers. 8x4 8 x 4. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step ...The expression startroot 64 r superscript 8 baseline endroot can be written as (64)1/8r8. This expression is asking for us to take the eighth root of 64, and then multiply it by 8. To solve this we can use the formula for radicals, which states that the nth root of a number a is equal to a1/n. In this case, n is equal to 8, and a is equal to 64.WILL MARK BRAINLIEST Which expression is equivalent to StartRoot StartFraction 25 x Superscript 9 Baseline y Superscript 3 Baseline Over 64 x Superscript 6 Baseline y Superscript 11 Baseline EndFraction EndRoot? Assume x Greater-than 0 and y > 0. answers.Which expression is equivalent to (One-sixteenth) Superscript negative 4? (-16)4 164 RootIndex 4 StartRoot one-sixteenth EndRoot. Negative (one-sixteenth) Superscript negative 4. Mathematics. Answer Comment. 1 answer: emmasim [6.3K] 3 years ago. 6 0. Answer: The simplified form of the expression is (16)⁴ or 65536.

WILL MARK BRAINLIEST Which expression is equivalent to StartRoot StartFraction 25 x Superscript 9 Baseline y Superscript 3 Baseline Over 64 x Superscript 6 Baseline y Superscript 11 Baseline EndFraction EndRoot? Assume x Greater-than 0 and y > 0. answers.What is the simplified form of StartRoot 10,000 x Superscript 64 Baseline EndRoot ? Answer: Factor 10000 into its prime factors. 10000 = 2^4 • 5^4. To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent. Factors which will be extracted are : 10000 = 2^4 • 5^4.Free math problem solver answers your precalculus homework questions with step-by-step explanations. ….

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What is the following simplified product? Assume x greater-than-or-equal-to 0 (StartRoot 6 x squared EndRoot 4 StartRoot 8 x cubed EndRoot) (StartRoot 9 x EndRoot minus x StartRoot 5 x Superscript 5 Baseline) 3 x StartRoot 6 x EndRoot x Superscript 4 Baseline StartRoot 30 x EndRoot 24 x squared 8 x Superscript 5 Baseline StartRoot 10 x EndRoot 3 x StartRoot 6 x EndRoot x Superscript 4 Baseline ...What is the simplified form of StartRoot 100 x Superscript 36 Baseline EndRoot ? 10x Superscript 18 10x Supe Get the answers you need, now! ... What is the simplified form of StartRoot 400 x Superscript 100 Baseline EndRoot ? 200x Superscript 10 200x Superscript 50 20x Superscript 10 20x Superscript 50. star. 4.8/5. heart. 74. …

12/16/2019. Mathematics; Middle School ... (RootIndex 3 StartRoot 54 a EndRoot) + 3 (RootIndex 3 StartRoot 2 a b Superscript 6 Baseline EndRoot) A. 6 b squared (RootIndex 3 StartRoot 2 a EndRoot) B. 12 b squared (RootIndex 3 StartRoot 2 a EndRoot C. 6 b squared (RootIndex 6 StartRoot 2 a EndRoot) D. 12 b squared …Find the derivative of the function. yequals=StartFraction 9 Over x Superscript 6 EndFraction 9 x6minus−StartFraction 3 Over x EndFraction. Here's the best way to solve it. Expert-verified.Thanks 16. star. star. star. star. star half outlined. rating answer section. star. star. star. star. star. Answer rating 4.7 ... (RootIndex 12 StartRoot x Superscript 5 EndRoot) D. x6. star. 4.8/5. heart. 91. verified. ... (StartRoot 6 EndRoot minus StartRoot 10 EndRoot) A. 6 StartRoot 2 EndRoot minus 2 StartRoot 30 EndRoot + 6 minus 2 ...

hot topic hemet ca A. StartRoot StartFraction 2 (2) (3) (3) (a) (a) (a) (a) (a) (a) (a) (a) Over 3 (3) (5) (5) (a) (a) EndFraction EndRoot B. StartRoot StartFraction 4 a Superscript 6 Baseline Over 25 EndFraction EndRoot C. StartFraction 5 Over 25 EndFraction StartRoot StartFraction a Superscript 8 Over a squared EndFraction EndRoot D.StartFraction 6 Over 15 ... why does my snapchat have a red dotcheat table elden ring Integral from 1 to StartRoot 2 EndRoot left parenthesis StartFraction u Superscript 5 Over 2 EndFraction minus StartFraction 1 Over u cubed EndFraction right parenthesis du∫12u52−1u3duequals=nothing. . There are 2 steps to solve this one. Expert-verified. great clips waterview To simplify the expression 4r2 + 4r3 + 8r2 + 8r3, combine like terms to get 12r2 + 12r3. Explanation: Simplify: ... Simplify: StartRoot 16 r Superscript 6 Baseline EndRoot 4r2 4r3 8r2 8r3. star. 4.2/5. heart. 8. verified. Verified answer. Jonathan and his sister Jennifer have a combined age of 48. If Jonathan is twice as old as his sister, how ...Calculus questions and answers. Differentiate the following function.Bold r left parenthesis t right parenthesisequalsleft angle 9 t Superscript 5 Baseline comma 18 StartRoot t EndRoot comma StartFraction 3 Over t EndFraction right angleQuestion content area bottomPart 1Bold r prime left parenthesis t right parenthesisequals. ihop near seattle airportinmate search pottawattamie countylow tide surf city nc today Question: Find the exact value of the expression. cotangent left bracket sine Superscript negative 1 Baseline left parenthesis negative StartFraction StartRoot 2 EndRoot Over 10 EndFraction right parenthesis right bracketcotsin?1?210 cot [sin^-1 (-root2/10)]=. Find the exact value of the expression. There are 2 steps to solve this one. jonesboro ga housing authority The question asks to simplify the expression StartRoot 144 x Superscript 36 EndRoot. First, we break down the square root of 144, which is 12, as 144 is a perfect square (12 x 12 = 144). Since the exponent of x is even (36), we can take the square root of x³⁶ by halving the exponent, which gives us x¹⁸. griffin roughton funeral home corsicana texasrollie baddies west real namesphynx cats for sale in kansas city What is the simplified form of StartRoot 10,000 x Superscript 64 Baseline EndRoot ? Answer: Factor 10000 into its prime factors. 10000 = 2^4 • 5^4. To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent. Factors which will be extracted are : 10000 = 2^4 • 5^4.